分析:把()3x+2y)看成是一个整体,再用"十"字相乘法,
(3x+2y-3)(3x+2y+7)-11
=(3x+2y)²+4(3x+2y)-21-11
=(3x+2y)²+4(3x+2y)-32
=[(3x+2y)+8][(3x+2y)-4]
=(3x+2y+8)(3x+2y-4)