(1)当3-2x≥0时,则3≤3-2x＜7,0≤-2x＜4,解得-2＜x≤0
（2）当3-2x＜0时,则3≤2x-3＜7,6≤2x＜10,解得3≤x＜5
综上所述：-2＜x≤0或3≤x＜5