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计算:
(1) (2x-1)(4x2+1)(2x+1);
(2) (2a-b+3)(2a-3+b);
(3) 4(a+2)2-7(a+3)(a-3)+3(a-1)2
人气:350 ℃ 时间:2020-02-03 09:15:07
解答
(1)(2x-1)(4x2+1)(2x+1),
=(4x2-1)(4x2+1),
=16x4-1.
(2)(2a-b+3)(2a-3+b),
=[2a+(3-b)][2a-(3-b)],
=4a2-(3-b)2
=4a2-b2+6b-9.
(3) 4(a+2)2-7(a+3)(a-3)+3(a-1)2
=4(a2+4a+4)-7(a2-9)+3(a2-2a+1),
=4a2+16a+16-7a2+63+3a2-6a+3,
=10a+82.
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