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解不等式4x/x²-7x+10≥1
人气:410 ℃ 时间:2020-04-22 09:09:37
解答
1-4x/(x^2-7x+10)<=0,(x^2-11x+10)(x^2-7x+10)<=0,(x-1)(x-10)(x-2)(x-5)<=0.
1<=x<2,或5
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