计算：x³/(x+1)-x²+x-1（x+1）分之x的立方减x的平方加x 减1_数学解答

计算：x³/(x+1)-x²+x-1
（x+1）分之x的立方减x的平方加x 减1

人气：369 ℃　时间：2020-01-27 20:25:56

解答

原式=x³/(x+1)-(x²-x+1)
=x³/(x+1)-(x+1)(x²-x+1)/(x+1)
=[x³-(x+1)(x²-x+1)]/(x+1)
=[x³-(x³+1)]/(x+1)
=-1/(x+1)