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分别以XY为半径画同心圆(X>Y),所得圆环的面积为14π,求式子[-6(x+y)²(x-y)³]²÷[3(x
求式子[-6(x+y)²(x-y)³]²÷[3(x +y)(x-y)²]²
人气:227 ℃ 时间:2020-02-02 19:37:19
解答
πx²-πy²=14πx²-y²=14分子[-6(x+y)²(x-y)³]²=[-6(x²-y²)²(x-y)]²=[-1176(x-y)]²分母[3(x +y)(x-y)²]²=[3(x²-y²)(...
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