选修4-5:不等式选讲
已知函数 f(x)=log2(|x-1|+|x-5|-a)
(1)当a=5时,求函数f(x)的定义域;
(2)当函数f(x)的值域为R时,求实数a的取值范围.
人气:213 ℃ 时间:2019-12-07 12:11:04
解答
(1)当a=5时,f(x)=log2(|x-1|+|x-5|-5),令|x-1|+|x-5|-5>0,当x<1时,|x-1|+|x-5|-5=(1-x)+(5-x)-5=1-2x>0,得x<12;当1≤x≤5时,|x-1|+|x-5|-5=-1<0不满足题意;当x>5时,|x-1|+|x-5|-5=2x-11>0...
推荐
猜你喜欢
- He felt ---at the news that he failed the exam A.frustrating B.rustration C.rustrated D.rustrate
- 如何画英语脑图
- 用所给词的适当形式填空,1,Tom's (.result)of the English exam is pretty good.
- 孩子挤出来(改成比喻句)
- 2x的平方-3y-2(x的平方-2y)
- 一道简单的物理题(质点运动)
- 甲,乙两地相距162千米,一列慢车从甲站出发,每小时走48千米,一列快车从乙站开出,每小时走60千米,试问:1.两列火车同时相向而行,多长时间可以相遇?2.两车同时反向而行,几小时后两车相距270千米?3.若两车相向而行,慢车先开出1小时,
- Look!That woman looks like our teacher .we are going to put it on the day after tomorrow.