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log25(底数)9(真数)×log27(底数)625(真数)=?
人气:296 ℃ 时间:2020-04-07 15:51:23
解答
log25(9)*log27(625)
=log(5^2)(3^2)*log(3^3)(5^4)
=[lg(3^2)/lg(5^2)]*[lg(5^4)/lg(3^3)]
=[2lg3*4lg5]/[2lg5*3lg3]
=4/3
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