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lim*[ln(1+3X)]/sin4X {X->0}求极限
lim*[ln(1+3X)]/sin4X {X->0} 求极限
人气:450 ℃ 时间:2019-11-19 21:52:56
解答
Lim[ln(1+3X)]/sin4X
x->0
=
Lim{[ln(1+3X)]/3X}*[4X/sin4X]*(3/4)
x->0
=
Lim{[ln(1+3X)]/3X}*Lim[4X/sin4X]*(3/4)
x->0.x->0
=1*1*3/4
=3/4
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