f(x) = 2asinxcosx+2bcos^2x = asin2x+b(cos2x+1) = asin2x+bcos2x+b f(0) = 8,asin0+bcos0+b = 0+b+b=8,b=4f(x) = asin2x+4cos2x+4 f(π/6)=6+3√3/2,asinπ/3+4cosπ/3+4 = a√3/2+2+4 = 6+3√3/2,a=3f(x) = 3sin2...