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已知m是实数,关于x的方程m^2x=m(x-3)+3的解不大于2,则m的范围是
人气:375 ℃ 时间:2020-02-06 07:00:44
解答
m^2x=m(x-3)+3
m^2x-mx=3-3m
(m^2-m)x=3-3m
x=(3-3m)/(m^2-m)
x<=2,则有:
(3-3m)/(m^2-2m)<=2
(3-3m)/(m^2-2m)-2<=0
(3-3m-2m^2+4m)/(m^2-2m)<=0
(2m^2-m-3)/(m(m-2))>=0
(2m-3)(m+1)/m(m-2)>=0
所以,m<=-1,02
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