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通分:x+4/x^2-8x+15,x-5/x^2+x-12,x-3/x^2-x-20
人气:121 ℃ 时间:2020-02-05 03:04:40
解答
x^2-8x+15=(x-3)(x-5) x^2+x-12=(x-3)(x+4) x^2-x-20=(x-5)(x+4)∴(x+4)/(x^2-8x+15)=(x+4)^2/(x-3)(x+4)(x-5)=(x^2+8x+16)/(x-3)(x+4)(x-5)(x-5)/(x^2+x-12)=(x-5)^2/(x-3)(x+4)(x-5)=(x^2-10x+25)/(x-3)(x+4)(x-...
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