4x-3y-3z=0 (1)x-3y-z=0 (2)(1)-(2)3x-2z=0z=(3/2)x(1)-(2)×34x-3y-3x+9y=0x-6y=0y=(1/6)x所以xz=x*(3/2)x=(3/2)x²xy=x*(1/6)x=(1/6)x²yz=(3/2)x*(1/6)x=(1/4)x²所以原式=[(1/6)x²+(1/4)x²...