你输入的题目可能有少量错误,应该是：
[a^(4/3)-8a^(1/3)b]÷[4b^(2/3)+2a^(1/3)b^(1/3)+a^(2/3)]÷[a^(1/3)-2b^(1/3)]÷[a^(1/3)b^(1/3)],如果前面说的是正确的,则可如下求解.
基本思路是：a=[a^(1/3)]³,8b=[2b^(1/3)]³,利用立方差公式将被除式分解因式,然后约分.
原式=a^(1/3)[a-8b]÷[4b^(2/3)+2a^(1/3)b^(1/3)+a^(2/3)]÷[a^(1/3)-2b^(1/3)]÷[a^(1/3)b^(1/3)]
=a^(1/3)[a^(1/3)-2b^(1/3)])]÷[a^(1/3)-2b^(1/3)]÷[a^(1/3)b^(1/3)]
=a^(1/3)÷[a^(1/3)b^(1/3)]=(1/b)乘以三次根号下的b².