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数学
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如图,AD平分∠BAC,DE⊥AB于E,DF⊥AC于F,且DB=DC,求证:EB=FC.
人气:246 ℃ 时间:2019-08-21 06:19:16
解答
证明:∵AD平分∠BAC,DE⊥AB于E,DF⊥AC于F,
∴DE=DF;
∵DE⊥AB于E,DF⊥AC于F.
∴在Rt△DBE和Rt△DCF中
DE=DF
DB=DC
∴Rt△DBE≌Rt△DCF(HL);
∴EB=FC.
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如图,AD平分∠BAC,DE⊥AB于E,DF⊥AC于F,且DB=DC,求证:EB=FC.
如图,AD平分∠BAC,DE⊥AB于E,DF⊥AC于F,且DB=DC,求证:EB=FC.
如图,AD平分∠BAC,DE⊥AB于E,DF⊥AC于F,且DB=DC,求证:EB=FC.
如图,AD平分∠BAC,DE⊥AB于E,DF⊥AC于F,且DB=DC,求证:EB=FC.
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