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因式分解x²-64,x²-6xy²+9y³,解方程组7x+3y=13,4x-y=2要过程
人气:223 ℃ 时间:2020-03-28 17:44:13
解答
x²-64,=(x-8)(x+8) x²y-6xy²+9y³=y(x²-6xy+9y²)=y(x-3y)² 7x+3y=13,①4x-y=2②①+②×3得:7x+3y+12x-3y=13+619x=19∴x=1 y=2
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