有人知道最小二乘法求线性回归方程是如何计算的吗?
人气:271 ℃ 时间:2020-01-30 21:45:44
解答
y = Ax + B:
a = sigma[(yi-y均值)*(xi-x均值)] /
sigma[(xi-x均值)的平方];
b = y均值 - a*x均值;
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