原式=[(x+y)(x-y)+2y²]/(x-y)
=(x²-u²+2y²)/(x-y)
=(x²+y²)/(x-y)原式=[(x+y)(x-y)+2y²]/(x-y)中[(x+y)(x-y)时神马意识通分如何通这样的分那就算了