已知（a-1）²+2b-3的绝对值+（c+1）²=0a-1=0;a=1;2b-3=0;b=3/2;c+1=0;c=-1;求3c分之ab-b分之a-c的值=1×3/2÷3×(-1)-1/(3/2)-(-1)=-1/2-2/3+1=-1/2+1/3=-1/6;很高兴为您解答,skyhunter002为您答疑解惑如...