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计算.(99…9)×(99…9)+(199…9) n个9 n个9 n个9
人气:215 ℃ 时间:2020-03-23 06:54:32
解答
(99…9)×(99…9)+(199…9)
=(99…9)×(99…9)+99…9+100...0
=(99…9)×(99…9+1)+100...0
=(99…9)×(100…0)+100...0
=100...0×(99...9+1)
=100...0×100...0
=100...0
2n个0
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