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化简sin^4α+cos^2α+sin^2α*cos^2α
人气:399 ℃ 时间:2020-04-10 17:02:40
解答
sin^4α+cos^2α+sin^2α*cos^2α
=sin^4α+sin^2α*cos^2α+cos^2α
=sin^2α(sin^2α+cos^2α)+cos^2α
=sin^2α*1+cos^2α
=sin^2α+cos^2α
=1
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