√6 x+3√2=√3 x+3 移项
√6 x-√3 x=3-3√2
(√6-√3)x=3-3√2
x=(3-3√2)/(√6-√3) 分母有理化
x=(3-3√2)(√6+√3)/[(√6+√3)(√6-√3)]
x=3(1-√2)(√6+√3)/(√6²-√3²)
x=3(1-√2)(√6+√3)/(6-3)
x=(1-√2)(√6+√3)
x=1×√6+1×√3-√2×6-√2×√3
x=√6+√3-2√3-√6
x=-√3