若不等式组
的解集是-1<x<1,则(a+b)
2009=______.
人气:178 ℃ 时间:2019-10-18 02:52:29
解答
由不等式得x>a+2,x<
b,
∵-1<x<1,
∴a+2=-1,
b=1
∴a=-3,b=2,
∴(a+b)
2009=(-1)
2009=-1.
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