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函数f(x)=sin(ωx+ф)+cos(ωx+ф)(ω>0,-π/2
人气:355 ℃ 时间:2019-08-23 21:31:28
解答
f(x)=sin(wx+a)+cos(wx+a)
=根号下2sin(wx+a+π/4)
最小正周期=2π÷w=π w=2
f(x)=根号下2sin(2x+a+π/4)
f(x)=根号下2sin(2x+a+π/4)=根号下2sin(π/4+a-2x)
2x+a=π-(π/4+a-2x)
a=3π/8
f(x)=根号下2sin(2x+5π/8)
当2kπ-π/2
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