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(a-b)分之1-(a+b)分之1+(a^2+b^2)分之2b计算,
人气:269 ℃ 时间:2020-04-02 18:57:51
解答
(a-b)分之1-(a+b)分之1+(a^2+b^2)分之2b=(a+b)/(a²-b²)-(a-b)/(a²-b²)+2b/(a²+b²)=(a+b-a+b)/(a²-b²)+2b/(a²+b²)=2b[1/(a²-b²)+1/(a²+b²)]=...
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