怎么计算:1.(x-2y+z)(-x+2y+z) 2.(2x-3y-1)(2x+3y-1)
人气:471 ℃ 时间:2020-03-29 17:29:50
解答
(x-2y+z)(-x+2y+z)=(z+x-2y)(z-(x-2y))=z^2-(x-2y)^2=z^2-x^2+4xy-4y^2(2x+3y-1)(2x-3y+1)=[2x+(3y-1)][2x-(3y-1)]=(2x)^2-(3y-1)^2=4x^2-(9y^2-6y+1)=4x^2-9y^2+6y-1
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