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已知a2-a-4=0,求a²-2(a²-a+3)-1/2(a²-a+4)-a的值
人气:123 ℃ 时间:2020-05-13 13:45:25
解答

a²-a-4=0
a²-a=4

a²-2(a²-a+3)-1/2(a²-a+4)-a
=a²-2a²+2a-6-1/2(4+4)-a
=-a²+2a-6-4-a
=-a²+a-10
=-(a²-a)-10
=-4-10
=-14
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