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数学
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已知x.x+y.y-6x-8y+25=0,求3x.x+5y的值
人气:403 ℃ 时间:2019-10-27 08:48:08
解答
可以得出
x.x+y.y-6x-8y+25 = x.x-6x+9+y.y-8y+16 = (x-3).(x-3)+(y-4).(y-4) = 0
因为(x-3).(x-3)>=0,(y-4).(y-4)>=0
所以x=3,y=4
所以3.x.x+5y=3.3.3+5.4=47
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已知x的平方+10+y的平方-8y+41=0,求3x-5y的值
加减(1){3x-8y=-4 5x+8y=4 (2){2x-5y=3 3x-5y=4 3){x+二分之一y=5 二分之一y-x=1(4)6x-5y=8 3x-4y=5
解方程组(1)3X+4Y=10 6X+8Y=8 (2)2X-5Y=3 4X-Y=6 (3)3X-5Y=10 5X+2Y=15
{2x+5y=15,3x+8y=-1;}中x,y的值为多少
3X+5Y=260;6X+8Y=500 怎么解?
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