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tan{arcsin[cosπ/4]+arccos[sinπ/3]+arctan√3}
人气:141 ℃ 时间:2019-12-24 20:14:17
解答
tan{arcsin[cosπ/4]+arccos[sinπ/3]+arctan√3}=
tan{arcsin(√2/2)+arccos(√3/2)+π/3}
=tan{π/4+π/6+π/3}
=tan{π/4+π/2}
=-tan(π/4)
=-1.
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