已知cos(a-b\2)=-1\9,sin(a\2-b)=2\3,且0
人气:297 ℃ 时间:2020-03-23 10:06:55
解答
∵cos(a-b/2)=-1/9,
0
推荐
- 已知cos[a-(b/2)]=-1/9,sin[(a/2)-b]=2/3.且π/2
- 已知0
- 已知cos=-1/9,sin=2/3,0
- cos(α-β/2)=-1/9,sin(α/2-β)=2/3,且π/2<α<π,0<β<π/2,求cos(α+β)的值
- 设cos(α-β/2)=-1/9 sin(α/2-β)=2/3 α∈(π/2,π)β∈(0,π/2)求cos(α+β)
- 一元二次方程两根之差的公式是什么
- 已知函数fx=根号3cos(2分之派-2x)+2cos方x+2
- he earned through his sharp practice of selling his 'protection'这句话怎样翻译,through怎样理解..
猜你喜欢