已知{3x-y+2z=14 4x-8y+z=7 求x+y+z的值
人气:134 ℃ 时间:2019-12-08 17:28:03
解答
3x-y+2z=14 ①
4x-8y+z=7 ②
∴①-2×②得 -5x+15y=0,即 x-3y=0 ③
∴x=3y代入②,得
4y+z=7 ④
∴③+④得 x+y+z=7
推荐
- 3X+7Y+Z=5,4X+8Y+2Z=3,则X+Y+Z的值为
- X+Y+Z=20,4X+3Y-Z=14.3X+4Y-2Z=16
- 化简-(-3x-y+2z)-{-x+【4x-(x-y-z)-3x+2z}
- 已知2x+5y+4z=15,7x+y+3z=14,3x+4y+2z=11.求4x+y+2z的值.
- 已知x,y,z满足方程组:4x-5y+2z=o;x+4y-3x=0,求x:y:z的值
- 已知向量a,b满足向量a的模=1,向量a*(向量a-向量b)=0,则向量b的模的取值范围是?
- 解释下面加点词的意思
- gee,do i know u,that such emotional young man
猜你喜欢