原式= (√3+√2-√5 )[√2( √3+√2+√5)]
=√2[ (√3+√2)-√5][(√3+√2)+√5]
=√2 [(√3+√2)²-(√5 )²]
=√2 (5+2√6-5)
=√2 (2√6)
=4√3