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1-[x-(1-x分之1)]^2除以x^2-2x+1分之x^2-x+1,其中x=-三分之一
人气:192 ℃ 时间:2020-06-21 20:15:26
解答
原式=1-(x-x²-1)²/(1-x)²÷(x²-x+1)/(x-1)²
=1-(x²-x+1)²/(x-1)²*(x-1)²/(x²-x+1)
=1-(x²-x+1)
=x²+x
=1/9-1/3
=-2/9
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