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已知4^m=8,16^n=6,求4^(2m-4n+1)
人气:227 ℃ 时间:2020-03-18 10:38:39
解答
4^(2m-4n+1)
=(4^2m)/(4^4n)*4
=4*(4^m)^2/(16^n)^2
=4*8^2/6^2
=64/9
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