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因式分解的一些题 x的三次方—9x+8 (x²—1)(x+3)(x+5)+12 x²+xy—6y²+x+13y—6 m&su
些题
人气:394 ℃ 时间:2020-04-27 13:07:26
解答
(1)x³-9x+8
=x³-1-9x+9
=(x-1)(x²+x+1)-9(x-1)
=(x-1)(x²+x+1-9)
=(x-1)(x²+x-8)
(2)(x²-1)(x+3)(x+5)+12
=(x+1)(x+3)(x-1)(x+5)+12
=(x²+4x+3)(x²+4x-5)+12
=(x²+4x)²-2(x²+4x)-15+12
=(x²+4x)²-2(x²+4x)-3
=(x²+4x-3)(x²+4x+1)
(3)x²+xy-6y²
=(x+3y)(x-2y)
抄的 选我哦哦
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