解析：y=sinxcos(x+∏／6)-1/2cos2x=sinxcos(x+π／6)-1/2 *(1-2sin²x)=sinxcos(x+π／6)+sin²x - 1/2=sinx*[cosxcos(π/6)-sinxsin(π/6) +sinx] -1/2=sinx*[cosxcos(π/6)+sinxsin(π/6)] -1/2=sinxcos[...