设四个连续奇数为2x-3.2x-1,2x+1,2x+3
(2x-3)^2+(2x-1)^2+(2x+1)^2+(2x+3)^2
=4x^2+9+4x^2+!+4x^2+1+4x^2+9
=16x^2+20
很明显,x=1合适
所以,四个连续奇数为-1,1,3,5