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若实数x满足x²-5x-1=0则x²+x+1/x²-1/x= x²-1/x²=
人气:215 ℃ 时间:2020-03-23 04:41:46
解答
x² - 5x - 1 = 0x² - 1 = 5xx - 1/x = 5x² +x + 1/x² - 1/x= (x²+ 1/x²) + (x - 1/x)= (x - 1/x)²+2 +(x - 1/x)= 5²+2+5= 32(x + 1/x)²= (x - 1/x)² + 4= 29x + ...
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