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分式的除法运算
x²-4y²/x²+y²+2xy÷2y+x/x²+xy
人气:133 ℃ 时间:2020-06-04 17:29:05
解答
(x²-4y²)/(x²+y²+2xy)÷(2y+x)/(x²+xy )=[(x+2y)(x-2y)]/[(x+y)^2]÷(2y+x)/x(x+y)=[x(x+2y)(x-2y)(x+y)]/(x+y)^2(2y+x)=[x(x-2y)]/(x+y)
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