> 数学 >
求定积分∫上限e+1,下限2.1╱(x-1)dx ∫上限π/2下限0.cos2x/(c谢谢了,
人气:282 ℃ 时间:2020-06-02 20:35:23
解答
∫上限e+1,下限2.1/(x-1)dx=∫上限e+1,下限2.1/(x-1)d(x-1) =ln(x-1)|(上限e+1,下限2 )=ln(e+1-1)-ln(2-1)=1-0=1
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版