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log(根号2+1)1/根号下3+2倍根号2=x 求x
人气:319 ℃ 时间:2020-05-08 19:28:42
解答
x=log(√2+1)[1/√(3+2√2)]
=-log(√2+1)[√(3+2√2)]
=-log(√2+1)(√(√2+1)^2)
=-log(√2+1)(√2+1)
=-1
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