sin(a+β)cos(r-β)-cos(β+a)sin(β-r)跟tan5π/4+tan5π/12 / 1-tan5π/12要怎么算
人气:350 ℃ 时间:2020-08-03 05:23:40
解答
sin(a+β)cos(r-β)-cos(β+a)sin(β-r)=sin(a+β)cos(r-β)-cos(a+β)sin[-(r-β)]=sin(a+β)cos(r-β)+cos(a+β)sin(r-β)=sin[(a+β)+(r-β)]=sin(a+r)[(tan5π/4)+(tan5π/12)]/[1-(tan5π/12)]=[(tan(π+π/4))...
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