> 数学 >
(1+2)(1+2^2/1)(1+2^4/1)(1+2^8/1)+2^16/1
人气:124 ℃ 时间:2020-04-16 00:36:03
解答
(1+2)(1+2^2/1)(1+2^4/1)(1+2^8/1)+2^16/1
=(1+2)(1+2^2/1)(1+2^4/1)(1+2^8/1)(1-2^8/1)/(1-2^8/1)+2^16/1
=(1+2)(1+2^2/1)(1+2^4/1)(1-2^4/1)/(1-2^8/1)+2^16/1
=(1+2)(1+2^2/1)(1-2^2/1)/(1-2^8/1)+2^16/1
=(1+2)(1-2)/(1-2^8/1)+2^16/1
=-3/(1-2^8/1)+2^16/1
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版