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因式分解
(1)x2-2x-8
(2)x2(x-1)-4(1-x)2
人气:379 ℃ 时间:2020-02-03 20:34:21
解答
(1)x2-2x-8=(x-4)(x+2);
(2)x2(x-1)-4(1-x)2
=(x-1)[x2-4(x-1)
=(x-1)[x2-4x+4)
=(x-1)(x-2)2
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