当x=2012,y=-2011时,求代数式(x^4-y^4)/(x2-2xy y2)·(y-x)/(x2 y2)
人气:294 ℃ 时间:2020-05-25 21:43:22
解答
(x^4-y^4)/(x2-2xy+ y2)·(y-x)/(x2+ y2)
=(x^2-y^2)(x^2+y^2)/(x-y)²·(y-x)/(x2+y2)
=-(x+y)
=-(2012-2011)
=-1
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