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(2/2002+4/2002+6/2002+...+2002/2002)-(1/2002+3/2002+5/2002+...2001/2002)
人气:374 ℃ 时间:2019-08-21 13:19:00
解答
(2/2002+4/2002+6/2002+...+2002/2002)-(1/2002+3/2002+5/2002+...2001/2002)
=(2/2002-1/2002)+(4/2002-3/2002)+...+(2002/2002-2001/2002)
=(1/2002)×1001
=1/2
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