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(-2/3a^2bc^3)(-3/4c^5)^2*1/3(ab^2c^3)/4/9abc^2
人气:123 ℃ 时间:2020-06-02 18:43:34
解答
(-2/3a^2bc^3)(-3/4c^5)^2×1/3(ab^2c^3)÷4/9abc^2
=-(2/3)(9/16)(1/3)(9/4)a^(2+1-1)b^(1+2-1)c^(3+25+3-2)
=-(9/32)a²b²c^29
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