用数学归纳法证明(n+1)(n+2)……(n+n)=2^n*1*3……(2n-1),从k到k+1,等式左边需增加的代数式为()
人气:109 ℃ 时间:2019-08-18 14:55:16
解答
[(2k+1)(2k+2)]/(k+1)wei shen me∵左边=(n+1)(n+2)……(n+n)∴n=k时 左边=(k+1)(k+2)……(k+k)当n=k+1时左边=(k+1+1)(k+1+2)(k+1+3)……(k+1+k+1)∴左边=(k+2)(k+3)(k+4)……(k+k)(2k+1)(2k+2)两式相比①(k+1)(k+2)(k+3)(k+4)……(k+k) ② (k+2)(k+3)(k+4)……(k+k)(2k+1)(2k+2) 可以得出左边要多乘(2k+1)(2k+2) 还要除于(k+1) 才能从①变②
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