角φ的终边经过点p(1,-1),则 φ=-π/4f(x)=sin(ωx-π/4)-1≤f(x1)≤1,-1≤f(x2)≤1则 |f(x1)|=|f(x2)|=1|x1-x2|的最小值为π/3f(x)的最小正周期为2π/3即 2π/ω=2π/3得 ω=3f(π/2)=sin(3π/2-π/4)=-√2/2...���� |f(x1)|=|f(x2)|=1����ô�õ��ģ�����������|f(x1)-f(x2)|=2�Dz���ì�ܣ�лл��不矛盾，当f(x1)=1时，f(x2)=-1，当f(x1)=-1时，f(x2)=1