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1/x的平方+3x+2+1/x的平方+5x+6+1/x的平方+4x+3
人气:158 ℃ 时间:2019-08-17 22:57:27
解答
1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+4x+3)=1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+1)(x+3)=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+1)(x+3)=1/(x+1)-1/(x+3)+1/(x+1)(x+3)=(x+3)/(x+1)(x+3)-(x+1)/(x+1)(x+3)+1/(x+1)(x+3)=[...
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